Logic:

• Get the array and its size

• As arrays start from 0 , so start from the last element , which is n-1 , where n is the array size
  

• Continue till 0th element is reached
• Print out all elements

Reverse Characters in an Array using Java :


public class CharReverse
{
       public static void main(String[] args)
       {         
            char[] characters = {'s','m', 'h', 't', 'i', 'r','o','g','l','a','-','d','n','e','i','r','f','a','q'};
            ReverseCharPrint A = new ReverseCharPrint();
            A.ReverseCharacters(characters,characters.length);
       }
}

class ReverseCharPrint
{   
      void ReverseCharacters(char[] chars, int ArraySize)
      {
            for (int i = ArraySize-1; i >= 0 ; i--)
            {
               System.out.print(chars[i]);
            }
      }

}

Output: qafriend-algorithms